Answer
True.
In fact, $f(t+nc)=f(t)$, where $n$ is an integer.
Work Step by Step
$f(t-2c)=f[(t-2c)+c]=f(t-c)$
$f(t-c)=f[(t-c)+c]=f(t)$. So:
$f(t-2c)=f(t)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - P.S. Problem Solving - Page 505: 4a
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