Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Chapter Test - Page 503: 17

Answer

$cot(arcsin~\frac{3}{8})=\frac{\sqrt {55}}{3}$

Work Step by Step

$y=arcsin~\frac{3}{8}$ $sin~y=\frac{3}{8},~~$ (Notice that $0°\lt y\lt90°$) $cos^2y+sin^2y=1$ $cos^2y=1-\frac{9}{64}=\frac{55}{64}$ $cos~y=\frac{\sqrt {55}}{8}$ $cot(arcsin~\frac{3}{8})=cot~y=\frac{cos~y}{sin~y}=\frac{\sqrt {55}}{3}$
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