Answer
$Amplitude=5$
$Period=6$
Work Step by Step
If $y=a~sin(bx)$
$Amplitude=|a|$
$Period=\frac{2\pi}{b}$
$y=-5~sin(\frac{\pi x}{3})$
$Amplitude=|-5|=5$
$Period=\frac{2\pi}{\frac{\pi}{3}}=2\pi\frac{3}{\pi}=\frac{6\pi}{\pi}=6$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.4 - Graphs of Sine and Cosine Functions - 6.4 Exercises - Page 464: 8
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