Answer
$Amplitude=\frac{2}{5}$
$Period=\frac{1}{5}$
Work Step by Step
If $y=a~cos(bx)$
$Amplitude=|a|$
$Period=\frac{2\pi}{b}$
$y=-\frac{2}{5}~cos(10\pi x)$
$Amplitude=|-\frac{2}{5}|=\frac{2}{5}$
$Period=\frac{2\pi}{10\pi}=\frac{1}{5}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - 6.4 - Graphs of Sine and Cosine Functions - 6.4 Exercises - Page 464: 12
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