Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - Review Exercises - Page 412: 13

Answer

$x=1$

Work Step by Step

$\frac{1}{3}=3^{-1}$ $(\frac{1}{3})^{x-3}=9$ $(3^{-1})^{x-3}=3^2$ $3^{-x+3}=3^2$ Using the One-to-One Property: $-x+3=2$ $-x=2-3=-1$ $x=1$
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