Answer
$x=0$
$x=3$
$x=-7$
Work Step by Step
$f(x)=0$
$x^4+4x^3-21x^2=0$
$x^2(x^2+4x-21)=0 $
$x^2=0$
$x=0$
$x^2+4x-21=0~~$ ($a=1,b=4,c=-21$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-4±\sqrt {4^2-4(1)(-21)}}{2(1)}=\frac{-4±\sqrt {100}}{2}=\frac{-4±10}{2}=-2±5$
$x=3$ or $x=-7$