Answer
$x=±2i$
$x=-2$
Work Step by Step
$f(x)=0$
$x^3+2x^2+4x+8=0$
$x^2(x+2)+4(x+2)=0$
$(x^2+4)(x+2)=0$
$x^2+4=0$
$x^2=-4$
$x=±\sqrt {-4}=±2i$
$x+2=0$
$x=-2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - Cumulative Test for Chapters 3-5 - Page 416: 5
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