Answer
False.
$\sqrt {f(x)}\ne\frac{1}{2}f(x)$
Work Step by Step
Use the Power Property:
$\frac{1}{2}f(x)=\frac{1}{2}\ln x=\ln x^{\frac{1}{2}}=\ln\sqrt x=f(\sqrt x)\ne\sqrt {f(x)}=\sqrt {\ln x}$
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