Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.2 - Logarithmic Functions and Their Graphs - 5.2 Exercises - Page 379: 49

Answer

$e^{-0.693...}=\frac{1}{2}$

Work Step by Step

$\ln\frac{1}{2}=-0.693...$ $e^{\ln\frac{1}{2}}=e^{-0.693...}$ (using the Inverse Property, page 375): $\frac{1}{2}=e^{-0.693...}$
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