Answer
Domain: $x\gt0$ or $(0,∞)$
x-intercept: $(\frac{1}{3},0)$
$x=0$ (y-axis) is the vertical asymptote.
Work Step by Step
$y=\log_3x+1$
Domain: $x\gt0$ or $(0,∞)$
x-intercept:
$y=\log_3x+1=0$
$\log_3x=-1$
$3^{-1}=x$
$x=\frac{1}{3}~~$ So, the x-intercept point is $(\frac{1}{3},0)$
$\log_ax→-∞$ when $x→0^+$. Also:
$\log_3x+1→-∞$ when $x→0^+$.
Then $x=0$ (y-axis) is the vertical asymptote.
