Answer
$f(x)=\log_3(1-x)$ corresponds to the graph labeled as (b).
Work Step by Step
Notice that: $f(0)=\log_3(1-0)=\log_31=0$. It gives us the point: $(0,0)$
Also, when $1-x→0^+$, that is, when $x→1^-$ $\log_3(1-x)→-∞$
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