Answer
$f(x)=\log_3(x-1)$ corresponds to the graph labeled as (d).
Work Step by Step
Notice that: $f(2)=\log_3(2-1)=\log_31=0$. It gives us the point: $(2,0)$
Also, when $x-1→0^+$, that is, when $x→1^+$ $\log_3(x-1)→-∞$
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