Answer
When $t=2000~years$:
$Q\approx7.846~grams$
Work Step by Step
$Q=10(\frac{1}{2})^{\frac{t}{5715}}$
When $t=2000~years$:
$Q=10(\frac{1}{2})^{\frac{2000}{5715}}=10(\frac{1}{2})^{0.349956}\approx7.846$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 5 - 5.1 - Exponential Functions and Their Graphs - 5.1 Exercises - Page 369: 64b
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