Answer
When $t=75,000~years$:
$Q\approx1.85~grams$
Work Step by Step
$Q=16(\frac{1}{2})^{\frac{t}{24,100}}$
When $t=75,000~years$:
$Q=16(\frac{1}{2})^{\frac{75,000}{24,100}}=16(\frac{1}{2})^{3.112}\approx1.85$
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