Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.1 - Exponential Functions and Their Graphs - 5.1 Exercises - Page 368: 30

Answer

$g(x)$ is a reflection of $f(x)$ about the origin, that is, $g(x)=-f(-x)$

Work Step by Step

Observe: $f(0)=(\frac{7}{2})^0=1$ which gives the point: $(0,1)$ $g(0)=-(\frac{7}{2})^0=-1$ which gives the point: $(0,-1)$ $f(1)=(\frac{7}{2})^1=\frac{7}{2}$ which gives the point: $(1,\frac{7}{2})$ $g(-1)=-(\frac{7}{2})^{-(-1)}=-\frac{7}{2}$ which gives the point: $(-1,-\frac{7}{2})$ $f(2)=(\frac{7}{2})^2=\frac{49}{4}$ which gives the point: $(2,\frac{49}{4})$ $g(-2)=-(\frac{7}{2})^{-(-2)}=-\frac{49}{4}$ which gives the point: $(-2,-\frac{49}{4})$
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