Answer
(b)
Work Step by Step
$f(x)=2^{x-2}=2^x.2^{-2}=\frac{1}{4}.2^x$
The exponential term has the form: $a^x$. So, the graph must be increasing.
$f(0)=\frac{1}{4}.2^0=\frac{1}{4}.1=\frac{1}{4}$. That is, the point $(0,\frac{1}{4})$ lies on the graph of $f(x)=2^{x-2}$
We conclude that the graph of $f(x)=2^{x-2}$ is (b)
