Answer
$y=2(x+3)^2-8$
Work Step by Step
Vertex: $(h,k)=(-3,-8)$
Standard form:
$y=a(x-h)^2+k$
$y=a[x-(-3)]^2+(-8)$
$y=a(x+3)^2-8$
Now, use the point $(-6,10)$ to find $a$:
$10=a(-6+3)^2-8$
$10+8=a(9)$
$a=\frac{18}{9}=2$
$y=2(x+3)^2-8$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - Review Exercises - Page 300: 18
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