Answer
$f(x)=(x+3)^2$
Work Step by Step
$x=-3$ must be a repeated zero so that we can find a polynomial of degree 2:
$f(x)=a[x-(-3)]^2=a(x+3)^2$
$a$ can be any value. If $a=1$:
$f(x)=(x+3)^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.2 - Polynomial Functions of Higher Degree - 3.2 Exercises - Page 261: 63
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