Answer
6
Work Step by Step
Solve the equation. Check if any of the solutions are extraneous. 1 does not satisfy the equation since the square root of a positive number is positive.
$\sqrt {x+10}=x-2$
$x+10=x^2-4x+4$
$x^2-5x-6=0$
(x-6)(x+1)=0
x=6,-1 (-1 is extraneous)
x=6
