Answer
a) See graph
b) $x=26$
Work Step by Step
We are given the function:
$f(x)=\sqrt{3x-14}-8$
a) Graph the function.
From the graph the zero is:
$x=26$
b) Determine the zeros algebraically:
$f(x)=0$
$\sqrt{3x-14}-8=0$
$\sqrt{3x-14}=8$
$(\sqrt{3x-14})^2=8^2$
$3x-14=64$
$3x=64+14$
$3x=78$
$x=\dfrac{78}{3}$
$x=26$
