Answer
$x=0$
$x=\sqrt 6$
$x=-\sqrt 6$
Work Step by Step
$f(x)=0$
$\frac{1}{3}x^3-2x=0$
$x(\frac{1}{3}x^2-2)=0$
$x=0$
or
$\frac{1}{3}x^2-2=0$
$\frac{1}{3}x^2=2$
$x^2=6$
$x=±\sqrt 6$
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