Answer
True.
$\displaystyle \sum_{j=1}^{6}2^j=\displaystyle \sum_{j=3}^{8}2^{j-2}$
Work Step by Step
$\displaystyle \sum_{j=1}^{6}2^j=2^1+2^2+2^3+2^4+2^5+2^6=2^{3-2}+2^{4-2}+2^{5-2}+2^{6-2}+2^{7-2}+2^{8-2}=\displaystyle \sum_{j=3}^{8}2^{j-2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - Review Exercises - Page 842: 104
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