Answer
(a) $_9P_2=72$
(b) $_{70}P_3=328,440$
Work Step by Step
(a) $_9P_2=\frac{9!}{(9-2)!}=\frac{9\times8\times7!}{7!}=72$
(b) $_{70}P_3=\frac{70!}{(70-3)!}=\frac{70\times69\times68\times67!}{67!}=328,440$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - Chapter Test - Page 843: 14
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