Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - Chapter Test - Page 843: 1

Answer

$a_1=-\frac{1}{5}$ $a_2=\frac{1}{8}$ $a_3=-\frac{1}{11}$ $a_4=\frac{1}{14}$ $a_5=-\frac{1}{17}$

Work Step by Step

$a_n=\frac{(-1)^n}{3n+2}$ $a_1=\frac{(-1)^1}{3(1)+2}=\frac{-1}{5}=-\frac{1}{5}$ $a_2=\frac{(-1)^2}{3(2)+2}=\frac{1}{8}$ $a_3=\frac{(-1)^3}{3(3)+2}=\frac{-1}{11}=-\frac{1}{11}$ $a_4=\frac{(-1)^4}{3(4)+2}=\frac{1}{14}$ $a_5=\frac{(-1)^5}{3(5)+2}=\frac{-1}{17}=-\frac{1}{17}$
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