Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.7 - Probability - 11.7 Exercises - Page 835: 44a

Answer

0.076

Work Step by Step

For a hand, the order or cards is unimportant. A (1234567) hand is the same as a (3124567) hand. We deal with combinations and use the combinations expression for the computation. $P=\frac{\text { no. of hands that suit us }}{\text { total ways to choose a } 7 \text { card hand }} = \frac{{ }_{8} C_{2} \cdot 100 C_{5}}{108 C_{7}}$ Hence, $P = \frac{\frac{8 !}{6 ! 2 !} \cdot \frac{100 !}{95 ! 5 !}}{\frac{108 !}{101 ! 7 !}}=0.076$ (Two cards out of eight possible wildcards. The other five out of the rest of the deck. We choose 7 out of a total of 108 cards )
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