Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.7 - Probability - 11.7 Exercises - Page 835: 42b

Answer

$\frac{19}{30}$

Work Step by Step

Total ways to insert paychecks is $5 !=120$ ways Now count the number of ways we can have 5,4,3,2,1,0 correct envelopes : 5 correct: 1 way 4 correct: not possible, because the fifth will be correct as well. 3 correct $:{ }_{5} C_{3} \cdot 1=10$ ways ( once the three envelopes that will contain the correct paychecks have been chosen, there is only one way to insert the paychecks so that the other two are wrong) 2 correct $:{ }_{5} C_{2} \cdot 2 \cdot 1=20$ ways ( once the two envelopes that contain the correct paychecks are chosen, for the three that remain, there are two ways to fill the next envelope incorrectly, then only one incorrect way to insert the remaining paychecks) 1 correct: $\quad 5 \cdot 3 \cdot 3 \cdot 1=45$ ways (five ways to choose which envelope has the correct paycheck, of the remaining four,three ways to fill the next envelope incorrectly, then three ways to fill the envelope whose correct paycheck was placed in another envelope, and only one way to fill the remaining two envelopesso that both are incorrect) 0 correct: $120-1-10-20-45=44 $ Answer for part (b) $\frac{45+20+10+1}{120} = \frac{19}{30}$
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