Answer
$-1,-4$
Work Step by Step
The determinant of a $2 \times 2$ matrix can be computed by using the formula $det =ps-qr$
where $det =\begin{bmatrix}p & q \\r & s\end{bmatrix}$
After simplifying, this matrix yields: $0=(x+3)(x+2) - (2)(1) $
We need to set the expression equal to $0$.
Thus, we have: $x^2+5x+4=0$
or, $(x+4)(x+1)=0$
So, $x=-1,-4$
