Answer
Both sides are the same.
Work Step by Step
The determinant of a $2 \times 2$ matrix can be computed by using the formula $det =ps-qr$
where $det =\begin{bmatrix}p & q \\r & s\end{bmatrix}$
Considering the left side, we have: $det=wcz-ycx$
Now, we have
$det=c(wz-xy)=wcz-ycx$
