Answer
Solutions:
$x=\frac{3}{2}+\frac{1}{2}i$
$x=\frac{3}{2}-\frac{1}{2}i$
Work Step by Step
$2x^2-6x+=5~~$ ($a=2,b=-6,c=5$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-6)±\sqrt {(-6)^2-4(2)(5)}}{2(2)}=\frac{6±\sqrt {-4}}{4}=\frac{6±2i}{4}=\frac{3}{2}±\frac{1}{2}i$
$x=\frac{3}{2}+\frac{1}{2}i$ or $x=\frac{3}{2}-\frac{1}{2}i$
