Answer
$+\sqrt 2, -\sqrt2, +\sqrt 3i, -\sqrt3i$
Work Step by Step
$x^4+x^2-6=0$
$(x^2+3)(x^2-2)=0$
Either $x^2+3=0$ giving $x = +\sqrt 3i, -\sqrt3i$
or $x^2-2=0$ giving $x = +\sqrt 2, -\sqrt2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - Chapter Test - Page 156: 10
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