Answer
$\frac{4z+2}{-3z}$
Work Step by Step
$\frac{\frac{z}{5}+\frac{1}{10}}{\frac{z}{20}-\frac{z}{5}}$
$\frac{20}{20}*\frac{\frac{z}{5}+\frac{1}{10}}{\frac{z}{20}-\frac{z}{5}}$
$\frac{\frac{20z}{5}+\frac{20}{10}}{\frac{20z}{20}-\frac{20z}{5}}$
$\frac{4z+2}{z-4z}$
$\frac{4z+2}{-3z}$