Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Exercise Set - Page 732: 75

Answer

$15\sqrt 3$ (or 25.98) $mi^2$

Work Step by Step

$s=1/2*(6+10+14)$ $s=1/2*(30)$ $s=15$ $A=\sqrt {s*(s-a)(s-b)(s-c)}$ $A=\sqrt {15*(15-6)(15-10)(15-14)}$ $A=\sqrt {15*9*5*1}$ $A=\sqrt {3*5*9*5}$ $A=5\sqrt {3*9}$ $A=15\sqrt {3}$
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