Answer
$3A=\begin{bmatrix}
9 & 12
\\
18 & -6
\\
3 & 0
\end{bmatrix}$
Work Step by Step
Multiplying each element of $
A=
\begin{bmatrix}
3 & 4
\\
6 & -2
\\
1 & 0
\end{bmatrix}
$ by $3,$ then
\begin{align*}
3A&=
\begin{bmatrix}
3(3) & 4(3)
\\
6(3) & -2(3)
\\
1(3) & 0(3)
\end{bmatrix}
\\\\&=
\begin{bmatrix}
9 & 12
\\
18 & -6
\\
3 & 0
\end{bmatrix}
.\end{align*}
Hence, $
3A=\begin{bmatrix}
9 & 12
\\
18 & -6
\\
3 & 0
\end{bmatrix}
.$
