Answer
$(8,4\pm2\sqrt{10})$
Work Step by Step
Adding the first and the second equation we get: $2x^2-16x=0\\2x(x-8)=0$
Thus $x=0$ or $x=8$
Plugging this into the second equation we get:
if $x=0$: $0-y^2-0+8y=24\\y^2-8y+24=0$
This has a negative discriminant, thus there is no solution here.
if $x=8$: $64-y^2-64+8y=-24\\y^2-8y-24=0$
Using the quadratic formula $y=4\pm2\sqrt{10}$
Thus the solutions are: $(8,4\pm2\sqrt{10})$
