Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Mixed Review - Page 657: 66

Answer

See below

Work Step by Step

Obtain: $2\ln x-2(\ln y +0.25\ln y)\\=2\ln x-2(1.25\ln y)\\=2\ln x-2.5 \ln y\\=\ln x^2-\ln y^{2.5}\\=\ln\frac{x^2}{y^{2.5}}$
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