Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Mixed Review - Page 657: 56

Answer

$$y=-8,\:x=-1$$

Work Step by Step

Solving the system of equations using substitution, we find: $$5\cdot \frac{13+2y}{3}+3y=-29 \\ y=-8 \\ x=\frac{13+2\left(-8\right)}{3}=-1$$
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