Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Skill Practice - Page 617: 5

Answer

$5\sqrt 5$ is the distance Midpoint is (2.5,1)

Work Step by Step

The distance formula is $\sqrt {(x_2-x_1)^2+(y_2-y_1)^2}$ The midpoint formula is $(x_2+x_1)/2,(y_1+y_2)/2$ $\sqrt {(5-0)^2+(-4-6)^2}$ $(5+0)/2,(-4+6)/2$
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