Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Problem Solving - Page 619: 53c

$\approx16.81$

The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence here (using part a)): $MP=\sqrt{(-1.5-3)^2+(8-11)^2}=\sqrt{29.25}$, $PV=\sqrt{(0-3)^2+(0-11)^2}=\sqrt{130}$, thus the total distance: $\sqrt{130}+\sqrt{29.25}\approx16.81$