Answer
See below
Work Step by Step
Given: $\frac{4}{x+1}-\frac{1}{x}=1\\\frac{4x-(x+1)}{x(x+1)}=1\\3x-1=x^2+x\\x^2-2x+1=0\\(x-1)(x-1)=0\\x=1$
Check: $\frac{4}{1+1}-\frac{1}{1}=1\\2-1=1$
Hence, the solution is $x=1$.
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 8 Rational Functions - Standardized Test Practice - Gridded Answer - Page 611: 9
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