Answer
See below
Work Step by Step
Given: $f(x)=\frac{x-3}{2x^2-4x+2}$
The domain of $f(x)$ is all real numbers for the values of $x$:
$2x^2-4x+2=0\\x^2-2x+1=0\\(x-1)^2=0\\x=1$
Thus, the domain doesn't contain $x=1$.
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