Answer
See below
Work Step by Step
Given: $\frac{20}{x^2+1}\lt2$
Enter $y_1=\frac{20}{x^2+1}$ and $y_2=2$ into a graphing calculator.
Graph the functions and use the intersect feature.
Hence, the solution is $x \in (-\infty, -3) \cup(3,\infty)$.
