Answer
$\approx8.935$
Work Step by Step
Plugging in $y=15$ into the formula we get: $15=0.51(1.46)^x\\\frac{15}{0.51}=(1.46)^x\\x=\log_{1.46}{\frac{15}{0.51}}\approx8.935$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.7 Write and Apply Exponential and Power Functions - 7.7 Exercises - Quiz for Lessons 7.6-7.7 - Page 536: 16
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