Answer
$y=\frac{5}{6}\cdot6^x$
Work Step by Step
Let $y=ab^x$.
Then our equations are: $5=ab^1$ and $30=ab^2$.
If we divide the second equation by the first one, we get: $6=b$.
Then $5=a\cdot6^1=6a\\a=\frac{5}{6}$.
Thus $y=\frac{5}{6}\cdot6^x$