Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Problem Solving - Page 521: 58

Answer

t=48.8

Work Step by Step

Given: $A=2400\\r=0.0225\\P=800$ Apply the formula: $A=Pe^{rt}$ Substitute: $2400=800e^{0.0225t}\\e^{0.0225t}=3\\ \ln(3)=\ln(e^{0.0225t})\\\ln(3)=0.0225t\\t=\frac{\ln (3)}{0.0225}\approx48.827\approx48.8$
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