Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Problem Solving - Page 521: 57

Answer

$\approx6967$

Work Step by Step

Plugging in $R=5$ into the given formula: $5=100e^{-0.00043t}\\0.05=e^{-0.00043t}\\\ln0.05=-0.00043t\\t=\frac{\ln0.05}{-0.00043}\approx6967$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.