Answer
$\log_350$
Work Step by Step
We know that $x\log_ab=\log_ab^x$, $\log_ab+\log_ac=\log_a(bc)$ and that $\log_ab-\log_ac=\log_a(b/c)$
Hence here $2(\log_320-\log_34)+0.5\log_34=2\log_320-2\log_34+\log_34^{0.5}=\log_320^2-\log_34^2+\log_32=\log_3400-\log_316+\log_32=\log_3(400/16\cdot2)=\log_350$