Answer
$\log_4(2^5x^7y^7)$
Work Step by Step
We know that $x\log_ab=\log_ab^x$ and that $\log_ab+\log_ac=\log_a(bc)$
Hence here $5\log_42+7\log_4x+4\log_4y=\log_42^5+\log_4x^7+\log_4y^4=\log_4(2^5x^7y^7)$
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