Answer
$41(1.089)^x=n$
Work Step by Step
Our initial amount is $41$, and the percent increase is: $0.089$. Then the number of breeding pairs is ($0\leq t\leq24$): $41(1+0.089)^x=41(1.089)^x=n$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Problem Solving - Page 485: 42a
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