Answer
See below
Work Step by Step
Graph the function: $p=48.28(1.06)^t$
We can see the price crosses $p=60$ between $t=3,t=4$. Thus the year when the average price of a ticket was about $\$60$: $2000+3=2003$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Problem Solving - Page 485: 41b
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