Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Mixed Review of Problem Solving - Lessons 6.1-6.3 - Page 436: 6

Answer

See below

Work Step by Step

Rewrite $16$ as a power of $4$: $$(\frac{16^{1/2}}{4^{1/2}})^5=[\frac{(4^2)^{1/2}}{4^{1/2}}]^5=(\frac{4}{4^{1/2}})^5=(4^{1/2})^5=2^5=32$$
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